=Electronics Hardware Questions=

Q:
Two capacitors are connected in parallel through a switch.
C1= 1uF, C2=0.25uF.
Initially the switch is open, C1 is charged to 10V. What happens if we close the switch?
No losses in the wires and capacitors.

A:
Hint from Hitequest
Since there are no losses in the circuit the amount of charge remains the same:
U1C1 + U2C2 = U3(C1+C2)
U3 = (U1C1+U2C2)/(C1+C2) = (10*1 + 0*0.25)/1+0.25 = 8
U3= 8V

Anonimous
What about that voltage on capacitor can not change immediately? It will be the spark and system will lose some energy.